Brooklyn 99 Captain Holt's Islander Puzzle
The Riddle In the 18th episode of the season 2, Capt. Holt presents this riddle: There's an island with 12 men, one of them is slightly lighter or heavier. You have to determine who has the different weight, using a seesaw. The exciting catch? You can only use it to measure three times. Here's a 12 balls version and multiple answers I've found: Twelve balls and a scale question on puzzling.stackexchange.com . There are top 2 answers, the most upvoted one is creatively brute-forcing it. Numbering the balls and weighing them via following order: Weighing 1: 1 4 8 12 / 5 7 10 11 Weighing 2: 2 6 9 11 / 4 7 10 12 Weighing 3: 5 8 9 10 / 3 6 11 12 And then, there are 24 different outcomes, which forces you to map all possible solutions if you wanted to prove it with a computer code: ==L : 3L L== : 1H R== : 1L ==R : 3H L=L : 8H R=L : 5H =L= : 2H L=R : 5L R=R : 8L =LL : 9H LL= : 7L RL= : 4L =LR : 6H LLR : 10L RLL : 12L =R=...